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What is the concentration of sugar ($C_{12}H_{22}O_{11}$) in mol $L^{–1}$ if its 20 g are dissolved in enough water to make a final volume up to 2 L?

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Mass of sugar = 20g
Volume of solution = 2L
Gram molar mass of sugar ($C_{12} H_{22} O_{11}$) = 342g
Molarity (M) of a solution is given by, =Number of moles of solute/Volume of solution in litres
$\Rightarrow \large\frac{20g/342g}{2L}=\frac{0.0585mol}{2L}$
$\Rightarrow 0.02925molL^{-1}$
Molar concentration of sugar = 0.02925 mol $L^{–1}$
Hence (D) is the correct answer.
answered Jun 6, 2014 by sreemathi.v

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