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# The amount of water that must be added to a 3 M HCl solution to make a 60 mL solution of 2 M HCl is ______ mL.

Volume of original solution ($V_1$) = ?
Molarity of final solution ($M_2$) = 2 M
Volume of final solution ($V_2$) = 0.060 L = 60 mL
By law of dilution, $V_1 M_1 = V_2M_2$
$V_1=\large\frac{2\times 60}{3}$$=40mL$