# Calculate the molality of 1 litre solution of 93% (w/v) $H_2SO_4$. The density of solution is 1.84 g/ml.

Molality = $\large\frac{w}{GMM}\times \frac{1000}{\text{Weight of solvent in grams}}$
$m=\large\frac{93}{98}\times \frac{1000}{91}$$=10.42moles/kg$