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Questions  >>  CBSE XII  >>  Math  >>  Application of Integrals
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Find the area bounded by the x-axis part of the curve $ y=1+\Large\frac{8}{x^2}$ and the ordinates x = 2 and x = 4 If the ordinate at x = a divides the area into two equal parts find ‘'a’'

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a=6^(1/2) Find total area A=4 A/2=2=(2[a-2]+8[[-1/a]+[1/2]) =a-(4/a) =a^2-4 •°•6=a^2 a=6^(1/2)
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