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The density of 2.0 M solution of acetic acid in water is 1.02 g $ml^{−1}$. Calculate the mole fraction of acetic acid.

1 Answer

Mass of acetic acid in 2.0 M acetic acid solution = $60\times 2=120gm\;per\;dm^3$
Mass of the solution = $V \times D = 1 \times 1.02 = 1.02 kg $
Mass of solvent = 1020 − 120 = 900 kg
Mole fraction of acetic acid =$\large\frac{2}{\Large\frac{900}{18}+2}=\frac{2}{50+2}$$=0.038$
Hence (B) is the correct answer.
answered Jun 6, 2014 by sreemathi.v
 

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