Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  AIMS  >>  Class12  >>  Chemistry  >>  Liquid Solutions
0 votes

The density of 2.0 M solution of acetic acid in water is 1.02 g $ml^{−1}$. Calculate the mole fraction of acetic acid.

Can you answer this question?

1 Answer

0 votes
Mass of acetic acid in 2.0 M acetic acid solution = $60\times 2=120gm\;per\;dm^3$
Mass of the solution = $V \times D = 1 \times 1.02 = 1.02 kg $
Mass of solvent = 1020 − 120 = 900 kg
Mole fraction of acetic acid =$\large\frac{2}{\Large\frac{900}{18}+2}=\frac{2}{50+2}$$=0.038$
Hence (B) is the correct answer.
answered Jun 6, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App