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# The density of 2.0 M solution of acetic acid in water is 1.02 g $ml^{−1}$. Calculate the mole fraction of acetic acid.

Mass of acetic acid in 2.0 M acetic acid solution = $60\times 2=120gm\;per\;dm^3$
Mass of the solution = $V \times D = 1 \times 1.02 = 1.02 kg$
Mole fraction of acetic acid =$\large\frac{2}{\Large\frac{900}{18}+2}=\frac{2}{50+2}$$=0.038$