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Home >> CBSE XII >> Math >> Application of Integrals

Find the area of the segment cut off from the parabola $ y^2=2x$ by the line $ y=4x-1$

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Find the area of the segment cut off from the parabola $ y^2=2x$ by the line $ y=4x-1$

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Find the area of the smaller region bounded by the curve $ \large\frac{x^2}{16}+\frac{y^2}{9}=1$ and the straight line $ \large\frac{x}{4}+\frac{y}{3}=1$

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Ask Questions, Get Answers

Find the area of the segment cut off from the parabola $ y^2=2x$ by the line $ y=4x-1$

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Please log in or register to answer this question.

Related questions

Find the area of the smaller region bounded by the curve $ \large\frac{x^2}{16}+\frac{y^2}{9}=1$ and the straight line $ \large\frac{x}{4}+\frac{y}{3}=1$

Show that the area enclosed by the circle $ x^2+y^2=64a^2$ and the parabola $y^2=12ax$ is $ a^2 \bigg(\frac{16}{\sqrt 3}+\large\frac {64\pi}{\sqrt 3}\bigg)$

Find the area included between the curves $ (x-1)^2+y^2=1\;and\;x^2+y^2=1$

Find the area bounded by the curve y = 2 cosx and the x-axis from x = 0 to x =$2\pi$

Sketch the region bounded by the curves $ y=x^2\;and\;y=\large\frac{2}{1+x^2}$ and find its area.

Sketch the region bounded by the curves $ y=\sqrt {5-x^2}\;and\; y=|x-1|$ and find its area.

Find the area bounded by the x-axis part of the curve $ y=1+\Large\frac{8}{x^2}$ and the ordinates x = 2 and x = 4 If the ordinate at x = a divides the area into two equal parts find 'a'

Find the area bounded by the x-axis part of the curve $ y=1+\Large\frac{8}{x^2}$ and the ordinates x = 2 and x = 4 If the ordinate at x = a divides the area into two equal parts find 'a'