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Home  >>  CBSE XII  >>  Math  >>  Application of Integrals

Show that the area enclosed by the circle $ x^2+y^2=64a^2$ and the parabola $y^2=12ax$ is $ a^2 \bigg(\frac{16}{\sqrt 3}+\large\frac {64\pi}{\sqrt 3}\bigg)$

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