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5 g of NaCl is dissolved in 1000 g of water. If the density of the resulting solution is 0.997 g per cc, calculate (iv) Mole fraction of the solute

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No. of moles of $H_2O = \large\frac{1000}{18}$$=55.55$
Total no. of moles = Mole of NaCl + Mole of H2O = 0854 + 55.55 = 55.6354
∴ Mole fraction of NaCl =$\large\frac{7.85}{98.66}$$=1.535\times 10^{-3}$
Hence (A) is the correct answer.
answered Jun 6, 2014 by sreemathi.v

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