# Hence obtain the work done in bringing a charge of $2 \times 10^{–9}\; C$ from infinity to the point P. Does the answer depend on the path along which the charge is brought?

$q= 2 \times 10^{-9}$
$W=qV= 2 \times 10^{-9} C \times 4 \times 10^{4}V$
$\quad= 8 \times 10^{-5} J$