Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

An assembly of charge $+q, -q, +q, -q ……..$ are placed at distance $x = 1m, x = 2m, x = 4m, x = 8m$ and so on, from the origon, in a plane. The potential at $x = 0,$ due to the charges would be ______.

Can you answer this question?

1 Answer

0 votes
Positive potential $V_+ =\large\frac{q}{4 \pi \in_0 (1)} +\frac{q}{4 \pi \in_0 (4)}+\frac{q}{4 \pi \in_0 (16)}....1\frac{q}{4 \pi \in_0} \bigg(1+\large\frac{1}{4} +\frac{1}{4} +\frac{1}{16} +....... \infty \bigg)$
$\qquad= \large\frac{q}{4 \pi \in_0 } \bigg( \large\frac{1}{1- (1/4) }\bigg) =\frac{q}{3 \pi \in_0}$
Negative potential $V_- =\large\frac{-q}{4 \pi \in_0 (2)} -\frac{q}{4 \pi \in_0 (8)}+\frac{q}{4 \pi \in_0 (32)}....$
$\qquad= \large\frac{q}{8 \pi \in_0} \bigg( 1+ \large\frac{1}{4} +\frac{1}{16} +,,,, \bigg)$
$\qquad= \large\frac{-q}{6 \pi \in_0}$
Net potential $V_{net}= \large\frac{q}{3 \pi \in_0} -\frac{q}{6 \pi \in_0}$
$\qquad= \large\frac{q}{6 \pi \in_0}$
answered Jun 7, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App