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# Potential in the x-y plane is given as $V = 5(x^2 + xy)\; volts$. Find the electric field at the point (1, –2).

$E_x=-\large\frac{dV}{dx} $$= -(10 x +5y) \qquad= -10+10=0 E_r=-\large\frac{dV}{dx}$$= -5 x=-5$
$\overrightarrow{E}=-5 \hat j V/m$