Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  AIMS  >>  Class12  >>  Physics  >>  Electric Charges and Fields
0 votes

Potential in the x-y plane is given as $V = 5(x^2 + xy)\; volts$. Find the electric field at the point (1, –2).

Can you answer this question?

1 Answer

0 votes
$E_x=-\large\frac{dV}{dx} $$= -(10 x +5y)$
$\qquad= -10+10=0$
$E_r=-\large\frac{dV}{dx} $$= -5 x=-5$
$\overrightarrow{E}=-5 \hat j V/m$
answered Jun 8, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App