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The work done in carrying a charge of $5 × 10^{-19}\; C$ upto a point is $2.4 × 10^{-5}\; joule$. What is the electric potential at that point?

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$(A)\;4.8 \times 10^{13} V$
Hence A is the correct answer.
answered Jun 8, 2014 by meena.p

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