Ask Questions, Get Answers

Home  >>  AIMS  >>  Class12  >>  Chemistry  >>  Liquid Solutions

The solubility of salt at 30$^{\large\circ}$C is 50. Calculate the weight of water required to prepare a saturated solution containing 90g of salt.

1 Answer

Solubility (S) = 50
Amount of salt ($w_1$) = 90g
We know that,
Solubility (S) =$\large\frac{w_1}{w_2}$$\times 100$----(1)
Substituting the above values in equation (1), we get
Weight of water (solvent)=$w_2=\large\frac{100w_1}{S}=\frac{100\times 90}{50}$$=180g$
Therefore, the weight of water required to prepare the solution is 180g.
Hence (A) is the correct answer.
answered Jun 9, 2014 by sreemathi.v

Related questions

Download clay6 mobile appDownload clay6 mobile app