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The solubility of salt at 30$^{\large\circ}$C is 50. Calculate the weight of water required to prepare a saturated solution containing 90g of salt.

1 Answer

Solubility (S) = 50
Amount of salt ($w_1$) = 90g
We know that,
Solubility (S) =$\large\frac{w_1}{w_2}$$\times 100$----(1)
Substituting the above values in equation (1), we get
Weight of water (solvent)=$w_2=\large\frac{100w_1}{S}=\frac{100\times 90}{50}$$=180g$
Therefore, the weight of water required to prepare the solution is 180g.
Hence (A) is the correct answer.
answered Jun 9, 2014 by sreemathi.v
 

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