Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  AIMS  >>  Class12  >>  Chemistry  >>  Liquid Solutions
0 votes

The solubility of a substance in water is 40. What is the maximum amount of solute required to prepare a saturated solution with 50g of water?

Can you answer this question?

1 Answer

0 votes
Solubility = S = 40
Amount of solute ($w_1)$ = ?
Amount of water = amount of solvent $(w_2)$ = 50g
We know that solubility =S=$\large\frac{w_1}{w_2}$$\times 100$
Amount of solute $w_1=\large\frac{S\times w_2}{100}$----(1)
Substituting the above values in equation (1), we get
Amount of solute=$W_1=\large\frac{40\times 50}{100}$$=5\times 4=20$
The amount of solute required to prepare the saturated solution is 20g.
answered Jun 9, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App