Browse Questions

# The solubility of a substance in water is 40. What is the maximum amount of solute required to prepare a saturated solution with 50g of water?

Amount of solute ($w_1)$ = ?
Amount of water = amount of solvent $(w_2)$ = 50g
We know that solubility =S=$\large\frac{w_1}{w_2}$$\times 100 Amount of solute w_1=\large\frac{S\times w_2}{100}----(1) Substituting the above values in equation (1), we get Amount of solute=W_1=\large\frac{40\times 50}{100}$$=5\times 4=20$