The partial pressure of ethane over a solution containing $6.56 \times 10^{-3 }$g of ethane is 1 bar. lf the solution contains $5 \times 10^{-2}$ g of ethane, then what shall be the partial pressure of the gas?

Answer 1

According to Henry’s Law ; $P_1=K_HX_1 $ and $P_2=K_HX_2$

$P_1=$1bar: $X_1=\large\frac{6.56\times 10^{-3}g}{30}$-----(i)

$P_2=?$

$X_2=\large\frac{5.00\times 10^{-2}g}{30}$-----(ii)

From eq(i) & eq(ii)

$\large\frac{P_1}{P_2}=\frac{X_1}{X_2}$

$\therefore P_2=\large\frac{5\times 10^{-2}}{6.56\times 10^{-3}}$

$P_2 = 7.62$ bar