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The partial pressure of ethane over a solution containing $6.56 \times 10^{-3 }$g of ethane is 1 bar. lf the solution contains $5 \times 10^{-2}$ g of ethane, then what shall be the partial pressure of the gas?

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According to Henry’s Law ; $P_1=K_HX_1 $ and $P_2=K_HX_2$
$P_1=$1bar: $X_1=\large\frac{6.56\times 10^{-3}g}{30}$-----(i)
$P_2=?$
$X_2=\large\frac{5.00\times 10^{-2}g}{30}$-----(ii)
From eq(i) & eq(ii)
$\large\frac{P_1}{P_2}=\frac{X_1}{X_2}$
$\therefore P_2=\large\frac{5\times 10^{-2}}{6.56\times 10^{-3}}$
$P_2 = 7.62$ bar
answered Jun 9, 2014 by sreemathi.v
 
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