Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  AIMS  >>  Class12  >>  Chemistry  >>  Liquid Solutions
0 votes

Henry’s law constant for the molality of methane in benzene at 298 K is $4.27 \times 10^5$ mm Hg. Determine the solubility of methane in benzene at 298 K under 760 mm Hg.

Can you answer this question?

1 Answer

0 votes
$K_H=4.27\times 10^5mm$ Hg
P=760mm Hg
$X=\large\frac{P}{K_H}=\frac{760}{4.27\times 10^5}$$=178\times 10^{-5}$
Hence (A) is the correct answer.
answered Jun 9, 2014 by sreemathi.v
Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App