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Vapour pressure of chloroform $(CHCl_3$) and dichloromethane ($CH_2Cl_2$) at 298 K are 200 mm Hg and 415 mm Hg respectively. (ii) mole fractions of each component in vapour phase.

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Calculation of mole fraction in vapour phase
To calculate the same, we need to first find the partial pressure of each component.
$P_{CH_2Cl_2} = 0.688 \times 415 mm$ Hg = 285.5 mm Hg
$P_{CHCl_3} = 0.312 \times 200$ mm Hg = 62.4 mm Hg
We also know that in vapour phase
$P_A = Y_AP_T$
Applying the above equation, we get
$Y_{CH_2Cl_2}$ = 285.5 mm Hg/347.9 mm Hg = 0.82
$Y_{CHCl_3}$= 62.4 mm Hg/347.9 mm Hg = 0.18
Hence (A) is the correct answer.
answered Jun 9, 2014 by sreemathi.v

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