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Calculate the potential at a point on the axis of a ring of charge of radius ‘a’. The charge on the ring is ‘q’ and distance of the observation point from the centre of the ring is ‘x’.

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$V= \large\frac{1}{4 \pi \in_0} \frac{q}{\sqrt {a^2+x^2}}$
Hence B is the correct answer.
answered Jun 9, 2014 by meena.p
 

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