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A uniform electric field is obtained by maintaining a potential difference of $700\; V$ between two metal plates kept 2 mm apart. Find the electric field intensity between them. What will be the force on a positive charge of $10 \mu C$, when placed positive the two plates?

1 Answer

$3.5 \times 10^{5} vm^{-1} ,3.5 N$
answered Jun 9, 2014 by meena.p

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