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Henry’s law constant for the solubility of methane in benzene at 25°C is $4.27 \times 10^5$ mm Hg. The mole fraction of methane in benzene is $1.5 \times 10^{−3}$ when the pressure is

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640.5 mm Hg
Hence (D) is the correct answer.
answered Jun 10, 2014 by sreemathi.v
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