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The vapour pressure of a liquid mixture containing liquids X and Y is 500 mm Hg at 75$^{\large\circ}$C. At 75$^{\large\circ}$C, the vapour pressure of pure liquids X and Y are 800 mm Hg and 300 mm Hg respectively. In vapour phase, the respective mole fractions of X and Y are

1 Answer

0.64 and 0.36
Hence (D) is the correct answer.
answered Jun 10, 2014 by sreemathi.v

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