logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

A point charge of magnitude $6 \mu C$ is placed at point M. The distance of point M from a test charge of unit magnitude, placed at point N, is $8 \times 10^{−2}\; m$. What will be the potential of point N if the test charge is replaced by a charge of magnitude $3 \mu C$?

Can you answer this question?
 
 

1 Answer

0 votes
$(C) 6.75 \times 10^5 V$
Hence C is the correct answer.
answered Jun 10, 2014 by meena.p
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...