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A point charge of magnitude $6 \mu C$ is placed at point M. The distance of point M from a test charge of unit magnitude, placed at point N, is $8 \times 10^{−2}\; m$. What will be the potential of point N if the test charge is replaced by a charge of magnitude $3 \mu C$?

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$(C) 6.75 \times 10^5 V$
Hence C is the correct answer.
answered Jun 10, 2014 by meena.p

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