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Write the set $ \bigg\{ \large\frac{1}{2}$$, \large\frac{2}{3}$$, \large\frac{3}{4}$$, \large\frac{4}{5}$$, \large\frac{5}{6}$$, \large\frac{6}{7} \bigg\}$ in the set-builder form.

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We see that each member in the given set has the numerator one less than the denominator. Also, the numerators begin from 1 and do not exceed 6.
Hence, in the set-builder form the given set is $ \{ x : x = \large\frac{n}{n+1}$, where $n$ is a natural number and $ 1 \leq n \leq 6$
answered Jun 10, 2014 by thanvigandhi_1

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