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A currently of dry air was passed through a solution of 2.5g of a non-volatile substance ‘X’ in 100g of water and then through water alone. The loss of weight of the former was 1.25g and that of the latter was 0.05g. Calculate (ii) molecular weight of the solute.

1 Answer

Hence (B) is the correct answer.
answered Jun 10, 2014 by sreemathi.v

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