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A solution containing 30 g of non-volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further, 18 g of water is then added to the solution and the new vapour pressure becomes 2.9 kPa at 298 K. What will be the molar mass of the solute P and vapour pressure of water at 298 K (respectively) ?

1 Answer

$34gmole^{-1}$
Hence (B) is the correct answer.
answered Jun 10, 2014 by sreemathi.v
 
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