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A charge $(q_1)$ is placed at the origin (O). Another charge $(q_2)$ is placed at point P 10 cm away from the origin, towards its right. On the line joining the two charges, the net electric potential is zero at point Q (which is 6 cm away from the origin), as shown in the given figure.What is the potential at point O due to the charge placed at point P?

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$(A) 1.2 \times 10^4 V$
Hence A is the correct answer.
answered Jun 10, 2014 by meena.p
 

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