Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

An electric potential of $9 \times 10^5\; V$ is caused at point P by two particles of charges $50 \mu C$ and $−20 \mu C$, as shown in the given figure.The point P is situated from the negative charge at a distance of

Can you answer this question?

1 Answer

0 votes
(D) 10.49 m
Hence D is the correct answer.
answered Jun 10, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App