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The electric potential V (in volt) varies with x (in metre) according to the relation $V = 5 + 4x^2$. The force experienced by a negative charge of $2 \times 10^{–6}C$ located at $x = 0.5\; m$ is

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$(D) 8 \times 10^{-6} N$
Hence D is the correct answer.
answered Jun 11, 2014 by meena.p

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