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A solution prepared by dissolving 8.95 mg of a gene fragment in 35.0 mL of water has an osmotic pressure of 0.335 torr at $25^{\large\circ}$C. Assuming the gene fragment is non-electrolyte, determine its molar mass.

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1 Answer

$1.4193\times 10^4gmol^{-1}$
Hence (A) is the correct answer.
answered Jun 11, 2014 by sreemathi.v
 

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