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Two point charges 4Q, Q are separated by 1 m in air. At what point on the line joining the charges is the "electric field intensity zero? Also calculate the electrostatic potential energy of the system of charges, taking the value of charge, $Q = 2 × 10^{-7}\; C.$

1 Answer

$x= \large\frac{1}{3}$$m $
$U= 1.44 mj$
answered Jun 11, 2014 by meena.p
 

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