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Home  >>  CBSE XII  >>  Math  >>  Vector Algebra
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If a, b & c are the lengths of the sides opposite respectively to the angles A, B & C of a $\bigtriangleup ABC,$ using vector method show that \[a)\cos A=\frac{b^2+c^2-a^2}{2bc} \qquad b)\;a=b\cos C+c \cos B.\]

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