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Two particles have equal masses of $5.0\; g$ each and opposite charges of $+4.0 \times 10^{–5}\; C$ and $– 4.0 × 10^{–5} C$. They are released from rest with a separation of 1.0 m between them. Find the speeds of the particles when the separation is reduced to 50 cm.

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$v= 53.7 m/s$
Hence B is the correct answer.
answered Jun 11, 2014 by meena.p

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