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Suppose that the same system of charges is now placed in an external electric field $E = A \times 1/r^2,$ where $A = 9 × 105 Cm^{–2.}$ What would the electrostatic energy of the configuration be?

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(D) 49.3 J
Hence D is the correct answer.
answered Jun 11, 2014 by meena.p
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