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Home  >>  AIMS  >>  Class12  >>  Chemistry  >>  Liquid Solutions
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The amount of ice that will separate on cooling a solution containing 50g of ethylene glycol in 200g water to –9.3$^{\large\circ}$C is : [$K_f = 1.86 K molality^{–1}$]

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$W_2 = 50 g, W_1 = x, K_f = 1.86 K molality^{−1}$
$M_2$ (for solute $C_2H_6O_2$) = 24 + 6 + 32 = 62g $mol^{−1}$
Freezing point depression ($\Delta T_f) = 9.3 ^{\large\circ}C$ (or) 9.3 K
$\Delta T_f=K_fm=\large\frac{K_f\times W_2\times 1000}{W_1\times M_2}$
$9.3=\large\frac{1000\times 1.86\times 50}{62\times W_2}$
$W_1=161.29$
Ice separated = 200 – 161.29 = 38.71 g
Hence (A) is the correct answer.
answered Jun 12, 2014 by sreemathi.v
 

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