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Calculate the boiling point of a solution containing 0.456 g of camphor (mol. mass = 152) dissolved in 31.4 g of acetone (b.p = 56.30$^{\large\circ}$C), if the molecular elevation constant per 100 g of acetone is 17.2$^{\large\circ}$C.

1 Answer

$56.46^{\large\circ}$
Hence (A) is the correct answer.
answered Jun 12, 2014 by sreemathi.v
 

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