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On dissolving 3.24 g of sulphur in 40g of benzene, the boiling point of the solution was higher than that of benzene by 0.81 K. What is the molecular formula of sulphur? ($K_b$ of benzene = 2.53 K kg $mol^{−1}$, atomic mass of sulphur = 32g $mol^{−1}$)

1 Answer

$S_8$
Hence (A) is the correct answer.
answered Jun 12, 2014 by sreemathi.v
 

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