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A 5% solution (by mass) of cane sugar in water has a freezing point of 271 K. Calculate the freezing point of 5% (by mass) solution of glucose in water. The freezing point of pure water is 273.15 K. (Molar mass of cane sugar =342 $g mol^{−1}$ and molar mass of glucose = 180 g $mol^{−1}$)

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Hence (B) is the correct answer.
answered Jun 12, 2014 by sreemathi.v
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