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Suppose X has a binomial distribution B(6,1/2) show that X = 3 is the most likely outcome.
cbse
class12
additionalproblem
kvquestionbank2012
ch13
q9
p41
math
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Feb 5, 2013
by
meena.p
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1
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Suppose X has a binomial distribution $ B\; \large($$6, \large\frac{1}{2})$. What is the most likely outcome and for what value of X, where x = 0, 1, 2, 3, 4, 5, 6?
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Jun 21, 2013
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Suppose X has a binomial distribution \(B\: ( 6, \frac{1}{2})\) . Show that X = 3 is the most likely outcome. Hint : P(X = 3) is the maximum among all \(P(x_i),\: x_i = 0,1,2,3,4,5,6\)
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Nov 27, 2012
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balaji.thirumalai
cbse
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The mean and variance of a binomial distribution are $ 4 \;and\;\frac{4}{3}.\;Find\;P(X\geq1).$
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cbse
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kvquestionbank2012
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The parameters n and p are 12 and 1/3 for a binomial distribution. Find standard deviation.
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Feb 5, 2013
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In a binomial distribution, the sum of mean and variance is 42. Product is 360. FInd the distribution.
asked
Feb 5, 2013
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meena.p
cbse
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In a hurdle race a player has to cross 10 hurdles. The probability that will clear each hurdle is 5/6, what is the probability that he will knock down fewer than 2 hurdles.
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Find the probability that sum of the numbers showing on the two dice is 8, given that atleast one dice doesnt show five.
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Feb 5, 2013
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meena.p
cbse
class12
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kvquestionbank2012
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