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The molal freezing point depression constant of benzene ($C_6H_6$) is 4.90 K kg $mol^{−1}$. Selenium exists as a polymer of the type ***. When 3.26 g of selenium is dissolved in 226 g of benzene, the observed freezing point is $0.112^{\large\circ}$C lower than pure benzene. Deduce the molecular formula of selenium. (Atomic mass of Se = 78.8 g $mol^{−1}$)

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Hence (A) is the correct answer.
answered Jun 13, 2014 by sreemathi.v

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