Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  AIMS  >>  Class12  >>  Chemistry  >>  Liquid Solutions
0 votes

The molal freezing point depression constant of benzene ($C_6H_6$) is 4.90 K kg $mol^{−1}$. Selenium exists as a polymer of the type ***. When 3.26 g of selenium is dissolved in 226 g of benzene, the observed freezing point is $0.112^{\large\circ}$C lower than pure benzene. Deduce the molecular formula of selenium. (Atomic mass of Se = 78.8 g $mol^{−1}$)

Can you answer this question?

1 Answer

0 votes
Hence (A) is the correct answer.
answered Jun 13, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App