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If 0.15g of a solute dissolved in 15 g of solvent is boiled at a temperature higher by 0.216$^{\large\circ}$C than that of the pure solvent. The molecular weight of the substance (molal elevation constant for the solvent is 2.16$^{\large\circ}$C kg/mol) is

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Hence (D) is the correct answer.
answered Jun 13, 2014 by sreemathi.v
 

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