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The molar freezing point constant for water is 1.86$^{\large\circ} C kg mole^{–1}$. If 342 gm of cane-sugar ($C_{12}H_{22}O_{11}$) are dissolved in 1000 gm of water, the solution will freeze at

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$– 1.86^{\large\circ}$C
Hence (A) is the correct answer.
answered Jun 13, 2014 by sreemathi.v

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