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Home  >>  CBSE XII  >>  Math  >>  Probability

The mean and variance of a binomial distribution are $ 4 \;and\;\frac{4}{3}.\;Find\;P(X\geq1).$

1 Answer

Given, np=4 and npq=4/3 Now npq=4/3 np(1-p)=4/3 4(1-p)=4/3 1-p=1/3 p=2/3 np=4 n(2/3)=4 n=6 p=2/3 1-q=2/3 q=1/3 Now,P(X>_1)=1-P(X=0) =1-(1/3)^6 =1-1/729 =728/729
answered Feb 26 by Sumitchn007
 

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