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0.440 g of a substance dissolved in 22.2 g of benzene lowered the freezing point of benzene by 0.567$^{\large\circ}$ C. The molecular mass of the substance ($K_f = 5.12^{\large\circ}kgCmol^{–1}$)

1 Answer

178.9
Hence (A) is the correct answer.
answered Jun 13, 2014 by sreemathi.v
 

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