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The ratio of the value of any colligative property for KCl solution to that for sugar is nearly ______ times.

1 Answer

$i_{KCl}=\large\frac{\text{Observed value of colligative property}}{\text{Normal value of colligative property}}$
$\Rightarrow \large\frac{\text{No.of particle furnished by KCl}}{\text{No.of particles before dissociation}}$$=2$
Hence (B) is the correct answer.
answered Jun 13, 2014 by sreemathi.v