Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  AIMS  >>  Class12  >>  Chemistry  >>  Liquid Solutions
0 votes

River water is found to contain 11.7% NaCl, 9.5% $MgCl_2$, and 8.4%. $NaHCO_3$ by weight of solution. Calculate its normal boiling point assuming 90% ionization of NaCl,70% ionization of $MgCl_2 $ and 50% ionization of $NaHCO_3$ ($K_b$ for water = 0.52 k kg $mol^{−1}$)

Can you answer this question?

1 Answer

0 votes
$i_{MgCl_2}=1+2\alpha=1+0.7\times 2=2.4$
$i_{NaHCO_3}=1+2\alpha=1+0.5\times 2=2.0$
$\Delta T_b=\large\frac{(1.9\times 0.2+2.4\times 0.1+2\times 0.1)\times 0.52\times 1000}{70.4}$
$\Rightarrow 6.0657^{\large\circ}$C
Boiling point of solution = 100 + 5.94 = $106.057^{\large\circ}$C
Hence (A) is the correct answer.
answered Jun 13, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App