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A potential difference of $250\; volt$ is applied across the plates of a capacitor of $10\; pF$. Calculate the charge on the plates of the capacitor.

1 Answer

Here,$V= 250 V$
$C= 10 \;p$
$F= 10 \times 10^{-12} F= 10^{-11}F$
$Q= CV=10^{-11} \times 250=2.5 \times 10^{-9}$
Hence A is the correct answer.
answered Jun 13, 2014 by meena.p
 
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