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Acetic acid ($CH_3COOH$) associates in benzene to form double molecules. 1.65 g of acetic acid when dissolved in 100g of benzene raised the boiling point by 0.36$^{\large\circ}$C. Calculate the van’t Hoff Factor and the degree of association of acetic acid in benzene (Molal elevation constant of benzene is 2.57).

1 Answer

0.508,98.3%
Hence (A) is the correct answer.
answered Jun 13, 2014 by sreemathi.v
 

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