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A slab of material of dielectric constant K has the same area as the plates of a parallel plate capacitor but has thickness $\large\frac{1}{2}$$d$ , where $d$ is the separation between the plates.Find the expression for the capacitance when the slab is inserted between the plates.

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$(B)\;\large\frac{V}{d}$
Hence B is the correct answer.
answered Jun 16, 2014 by meena.p
 

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