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The figure given shows two identical capacitors $C_1$ and $C_2$, each of $2 \mu F$ capacitance, connected to a battery of $5\; V$. Initially switch 'S' is closed. After some times is left open and dielectric slabs of dielectric constant K = 5 are inserted to fill completely the space between the plates of the two capacitors. How will the charge?

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No change in charge
answered Jun 16, 2014 by meena.p
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