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A parallel plate capacitor with air between the plates has a capacitance of $8\; pF$. The separation between the plates is now reduced by half and the space between them is filled with a medium of dielectric constant $5$. Calculate the value of capacitance of the capacitor in the second case.

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$(A)\;C_1\bigg( \large\frac{2 k_1k_2}{k_1+K_2}\bigg)$
Hence A is the correct answer.
answered Jun 16, 2014 by meena.p
 

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